9.一元函数积分学的计算

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基本公式

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不定积分的积分法

凑微分法

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换元法

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分部积分法

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有理函数的积分

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定积分的计算(例题)

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点火公式

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变限积分的计算

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重要结论

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反常积分的计算(例题)

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$$ Γ$$函数

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tips:

倒代换;区间重现

注意:

$$\int_{0}^{\pi} x f(\sin x) , dx$$

$$\int_{0}^{\pi} x f(\sin x) , dx = \int_{\pi}^{0} (\pi - t) f(\sin(\pi - t)) (-dt) = \int_{0}^{\pi} (\pi - t) f(\sin t) , dt$$

注意到 $$\sin(\pi - t) = \sin t$$,因此积分化简为:
$$\int_{0}^{\pi} x f(\sin x) , dx = \int_{0}^{\pi} (\pi - t) f(\sin t) , dt$$

将原积分记为 $I = \int_{0}^{\pi} x f(\sin x) , dx$
又$I = \int_{0}^{\pi} (\pi - t) f(\sin t) , dt$

将这两个表达式相加:
$2I = \int_{0}^{\pi} x f(\sin x) , dx + \int_{0}^{\pi} (\pi - x) f(\sin x) , dx = \int_{0}^{\pi} \pi f(\sin x) , dx$
$2I = \pi \int_{0}^{\pi} f(\sin x) , dx$

又考虑到$f(sinx)$关于$x=\frac{\pi}{2}$对称

$\int_{0}^{\pi} x f(\sin x) , dx = \frac{\pi}{2} \int_{0}^{\pi} f(\sin x) , dx= \pi \int_{0}^{\frac{\pi}{2}} f(\sin x) , dx$